The Surveyor's Calculator contains useful formulas for height(h) by drop time calculating ranges (a) and elevations (Y) based on measurable observations (`theta_1, theta_2,` and x). It provides a height estimate (h) base on time of a vertical drop, and it also provides a simple Interpolation (linear) calculation.
If a projectile is launched at a speed uufrom a height H above the horizontal axis, gg is the acceleration due to gravity, and air resistance is ignored, its trajectory is
y=H+xtanθ−x2g2u2(1+tan2θ),y=H+xtanθ−x2g2u2(1+tan2θ),
and its maximum range is
Rmax=ugu2+2gH−−−−−−−−√.Rmax=ugu2+2gH.
I would like to derive the above Rmax,Rmax, and here's what I've done:
substitute (x,y)=(R,0)(x,y)=(R,0) into the trajectory equation;
differentiate the result with respect to θ;θ;
substitute (R,dRdθ)=(Rmax,0).
Additional formulas could be easily Linear Interpolation added to this calculator. Please feel free to make suggestions by adding comments below.
projectile motion
motion of an object subject only to the acceleration of gravity
range
maximum horizontal distance a projectile travels
time of flight
elapsed time a projectile is in the air
trajectory
path of a projectile through the air
REFERENCE
[1]Projectile motion
Source: Wikipedia
URL: https://courses.lumenlearning.com/suny-osuniversityphysics/chapter/4-3-projectile-motion/
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