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Pyramid Frustum (polygon base) - surface area

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Aug 21, 2020, 8:16:13 PM
Created by
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Sep 30, 2014, 2:42:53 PM
SA=n4[(b2+B2)cot(πn)+(B2-b2)2sec2(πn)+4h2(B+b)2]SA=n4[(b2+B2)cot(πn)+(B2b2)2sec2(πn)+4h2(B+b)2]
(n)number of sides
(h)height
(b)side
(B)side
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0dc27079-48b0-11e4-a9fb-bc764e2038f2

The Surface Area of Pyramid Frustum calculator computes the surface area of the frustum of right pyramid with two regular polygon bases with the same number of sides (n) separated by a  height (h).  The base polygons are defined by the number of sides (n) and the equal side lengths of 'b" and 'B" of the two polygons respectively (see diagram)./attachments/0dc27079-48b0-11e4-a9fb-bc764e2038f2/Pyramid - frustum.png

INSTRUCTIONS: Choose units and enter the following:

  • (n) Number of Sides on the Polygon
  • (h) Height of the Frustum
  • (b) Length of the Top Sides
  • (B) Length of the Bottom Sides

Pyramid Frustum Surface Area (SA): The calculator returns the surface area in square meters.  However this can be automatically converted to compatible units via the pull-down menu.

The Math / Science

A right pyramid has the base of a polygon of equal length sides.  The diagrams show a four sided (n = 4) polygon and a six sided (n = 6) polygon respectively./attachments/0dc27079-48b0-11e4-a9fb-bc764e2038f2/pyramid frustum - polyon base.png


This equation, Pyramid Frustum (polygon base) - surface area, is used in 1 page
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