Distance with Earth Gravity

Last modified by

on

Jul 24, 2020, 6:28:07 PM

Created by

on

Sep 23, 2015, 12:21:58 AM

d x = x + v \cdot t + \frac{1}{2} \cdot 9.8 \cdot t^{2}

$dx = "x" + "v" * "t" + 1/2 * 9.8 * "t" ^2$

(x) This is the initial distance.

$(x) "This is the initial distance."$

(v) This is the initial velocity

$(v) "This is the initial velocity"$

(a) This is the constant gravity acceleration

$(a) "This is the constant gravity acceleration"$

(t) This is the time of travel

$(t) "This is the time of travel"$

(S 0) this is the space object

$(S0)"this is the space object"$

• Acceleration Due to Gravity (Earth) by KurtHeckman

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