IT Grade

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Jul 24, 2020, 6:28:07 PM

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Aug 12, 2016, 6:53:57 PM

T = 10^{0.2 \cdot (I T G - 1)} \cdot (0.45 \cdot \sqrt[3]{D} + 0.001 \cdot D)

$T = 10^(0.2*( ITG -1))*(0.45*root3 D +0.001* D )$

(I T G) IT Grade

$(ITG)"IT Grade"$

(D) geometric mean dimension

$(D)"geometric mean dimension"$

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The IT Grade refers to the International Tolerance Grade of an industrial process define in ISO 286. This grade identifies what tolerances a given process can produce for a given dimension. This specific tolerance for a particular IT grade is calculate via the following formula:
$T = 10^{0.2 \cdot (I T G - 1)} \cdot (0.45 \cdot \sqrt[3]{D} + 0.001 \cdot D)$ $T =10^(0.2*(ITG-1))*(0.45*root3D+0.001*D)$ , where:

$T$ $T$ = tolerance
$I T G$ $ITG$ = IT Grade, a positive integer
$D$ $D$ = geometric mean dimension
Think of $D$ $D$ as being the key dimension on the part and $T$ $T$ as being the required tolerance on the key dimension. The larger $I T G$ $ITG$ , the looser the tolerance.

References

Wikipedia (https://en.wikipedia.org/wiki/IT_Grade)

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