Quantcast

Radius of Displaced Circle

Last modified by
on
Jul 24, 2020, 6:28:07 PM
Created by
on
May 20, 2014, 7:59:06 PM
`"radius" = sqrt( ( "x" - "h" )^2 + ( "y" - "k" )^2 )`
`"X-coordinate of the Circle's Center"`
`"Y-coordinate of the Circle's Center"`
`"X-coordinate of a Point on the Circle"`
`"Y-coordinate of a Point on the Circle"`
Tags
UUID
32f2a2d9-e059-11e3-b7aa-bc764e2038f2

This equation computes the radius of a circle given that you know the circle's center  and a point anywhere on the circle. The circle's center can be placed anywhere in the X-Y Plane.

Our circle in this equation is centered at the point (h,k) and the point on the circle is (x,y)

Inputs:

  • h - x-coordinate of the circle's center
  • k - y-coordinate of the circle's center
  • x - x-coordinate of a point on the circle
  • y - y-coordinate of a point on the circle

Note all coordinates ( h, k, x, y ) should be in the same length units.

/attachments/32f2a2d9-e059-11e3-b7aa-bc764e2038f2/RadiusofDisplacedCircle-illustration.png


  • Comments
  • Attachments
  • Stats
No comments
This site uses cookies to give you the best, most relevant experience. By continuing to browse the site you are agreeing to our use of cookies.