THD Sawtooth Wave

Last modified by

on

Jul 24, 2020, 6:28:07 PM

Created by

on

Mar 31, 2015, 10:06:45 PM

{THD}_{F} (Sawtooth Wave) = \sqrt{\frac{π^{2}}{8} - 1}

$"THD"_F("Sawtooth Wave") = sqrt(pi^2/8 - 1)$

Share Result

•

π

$pi$ by MichaelBartmess

No comments

No attachments

Last 12 Months

This site uses cookies to give you the best, most relevant experience. By continuing to browse the site you are agreeing to our use of cookies.