BTU(th) / (lb R) -to- J / (kg K)

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on

Jul 24, 2020, 6:28:07 PM

Created by

on

Mar 12, 2015, 6:30:35 AM

\frac{J}{k g \cdot^{\circ} K} = \frac{{BTU}_{(th)}}{pound \cdot^{\circ} R} \cdot 4184

$J/(kg*""^@"K") = "BTU"_"(th)" / ("pound" * ""^@"R") * 4184$

Specific Heat Capacity

$"Specific Heat Capacity"$

• lb-to-kg by MichaelBartmess

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