$\int_{a}^{b} \frac{1}{\sqrt{c^{2} + x^{2}}} d x$ $int_a^b1/sqrt(c^2+x^2)dx$

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Jul 24, 2020, 6:28:07 PM

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Jun 11, 2014, 2:08:51 AM

\int_{a}^{b} \frac{1}{\sqrt{c^{2} + x^{2}}} d x = \sin^{- 1} (b \cdot | \frac{1}{c} |) - \sin^{- 1} (a \cdot | \frac{1}{c} |)

$int_a^b1/sqrt(c^2+x^2)dx = sin^-1(b*abs(1/c)) - sin^-1(a*abs(1/c))$

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This equation calculates the definite integral for the expression f(x) = $\frac{1}{\sqrt{c^{2} - x^{2}}}$ $1/sqrt(c^2 - x^2)$ . It returns an answer expressed in units of radians.

Please note that this does not calculate an integral where there is a coefficient in front of x.

** written by Hunter Metcalfe

This equation,

\int_{a}^{b} \frac{1}{\sqrt{c^{2} + x^{2}}} d x

$int_a^b1/sqrt(c^2+x^2)dx$ , references 0 pages

This equation,

\int_{a}^{b} \frac{1}{\sqrt{c^{2} + x^{2}}} d x

$int_a^b1/sqrt(c^2+x^2)dx$ , is used in 0 pages

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$\int_{a}^{b} \frac{1}{\sqrt{c^{2} + x^{2}}} d x$ $int_a^b1/sqrt(c^2+x^2)dx$

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$\int_{a}^{b} \frac{1}{\sqrt{c^{2} + x^{2}}} d x$ $int_a^b1/sqrt(c^2+x^2)dx$