$\int_{a}^{b} (\frac{1}{{cos}^{2} (x)}) d x$ $int_a^b (1/(cos^2(x)))dx$

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Jul 24, 2020, 6:28:07 PM

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Aug 1, 2015, 9:02:12 PM

\int_{a}^{b} (\frac{1}{{cos}^{2} (x)}) d x = tan (b) - tan (a) + 0.0

$int_a^b (1/(cos^2(x)))dx = tan( "b" ) -tan( "a" ) + 0.0$

(a) Lower Limit

$(a)"Lower Limit"$

(b) Upper Limit

$(b)"Upper Limit"$

(C) Constant

$(C)"Constant"$

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94e0ee19-3890-11e5-a3bb-bc764e2038f2

This vCalc equation computes the definite integral of $F (x) = \frac{1}{{cos}^{2} (x)}$ $F(x) = 1/(cos^2(x))$ . ¹

^ Gradshteyn, I.S. and Ryzhik, I.M. Table of Integrals, Series and Products. Seventh Edition. Academic Press - 2007. ISBN-13: 978-0-12-373637-6, ISBN-10: 0-12-373637-4. eq 2.01-8

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∫ba(1cos2(x))dx∫ba(1cos2(x))dxint_a^b (1/(cos^2(x)))dx