`-h=1/2(-g)Deltat^2`

$-h = 1/2(-g) Deltat ^2$

Enter a value for all fields

The Vertical Distance equation, $Delta y= 1/2*a_y* Deltat^2$ , calculates the vertical distance traveled ( $Delta y$ ) by an object from the origin after a period of time (t), the objects initial velocity and displacement are zero and a constant acceleration (a).

Note: this is a form of the following equation with no initial distance (x₀= 0). $dx = x_0 + v_0*t + 0.5*a*t^2$

Usage

Acceleration (a) is typically - m/s² to represent the negative (downward) force of gravity.

Reference

Light and Matter(Dr. Benjamin Crowell) Chapter 6.2 Coordinates and components