`int_a^b (1/sqrt(x^2+1))dx`
Last modified by
on
Nov 4, 2021, 4:43:40 PM
Created by
on
Aug 1, 2015, 11:55:47 PM
`int_a^b (1/sqrt(x^2+1))dx = ln( "b" + sqrt(b^2 +1)) - ln( "a" + sqrt(a^2 +1)) + 0.0 `
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UUID | d4b18e01-38a8-11e5-a3bb-bc764e2038f2 |
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This vCalc equation computes the definite integral of `F(x) = 1/(1-x^2)`.
- ^ Gradshteyn, I.S. and Ryzhik, I.M. Table of Integrals, Series and Products. Seventh Edition. Academic Press - 2007. ISBN-13: 978-0-12-373637-6, ISBN-10: 0-12-373637-4. eq 2.01-9
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