Last modified by
on
Jul 24, 2020, 6:28:07 PM
Created by
on
Jan 16, 2014, 6:07:14 AM
∫baz⋅(z+v)ndz=(b+v)n+1⋅((n+1)⋅b-v)(n+1)⋅(n+2)-(a+v)n+1⋅((n+1)⋅a-v)(n+1)⋅(n+2)
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This equation computes the definite integral for the expression F(z)=z⋅(z+v)n.
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