$int_a^b1/(v^2+z^2)dz$

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on

Jul 24, 2020, 6:28:07 PM

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on

Dec 27, 2013, 8:10:29 PM

$int_a^b1/(v^2+z^2)dz = (1/ "v" )*tan^-1( "b" / "v" ) - (1/ "v" )*tan^-1( "a" / "v" ) + 0.0$

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This equations calculates the definite integral for the expression $F(z) = 1/(v^2 + z^2)$ .

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∫ba1v2+z2dzint_a^b1/(v^2+z^2)dz