Sum_014-3

`sum_(k=1)^n1/ "[(p+(k-1)q ] (p+kq)...[p+(k+m)q]" = 1/(( m +1) q ) {1/ ( p ( p + q )...( p + m * q ) ) - 1/(( p + n * q ) [ p +( n +1) q ]...[ p + ( n + m ) q ] ) }`

Enter a value for all fields

1/((m+1) q) {1/ (p(p+q)...(p+mq) ) - 1/((p+nq) [p+(n+1)q ]...[p + (n+m) q] ) }