atm-to- ${ft}_{H2O}$ $"ft"_"H2O"$

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Last modified by

on

Jul 24, 2020, 6:28:07 PM

Created by

on

Dec 31, 2013, 6:16:18 PM

{ft}_{H_{2} O} = atm \cdot \frac{33.899524252 {ft}_{H_{2} O}}{atm}

$"ft"_(H_2"O") = "atm" * (33.899524252 " ft"_(H_2"O")) / "atm"$

{Atmospheres}_{Standard}

$"Atmospheres"_"Standard"$

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e6d090da-da27-11e2-8e97-bc764e04d25f

This equation converts input standard atmospheres (atm) into pressure units of feet of water

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{ft}_{H2O}

$"ft"_"H2O"$ , references 0 pages

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{ft}_{H2O}

$"ft"_"H2O"$ , is used in 0 pages

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atm-to-ftH2OftH2O"ft"_"H2O"