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Dielectric Constant (Relative Permittivity)

εr=εε0
ε
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This equation can calculate relative permittivity.  it assumes that the permittivity (ε) is measured in Farads per meter.  For some common dielectric constants, please see this Dielectric Constant lookup equation.

Brief Version

εr is inversely proportional to how much stronger the electric field is in a given material compared to vacuum.  

More

Polarization (P) is what happens when an electric field (E) pushes on a material where the charges can move a little, but aren't fully free.  You can think of it as the charges being shifted so that they may not cancel out in a given area.  However, the charge of the entire material is still conserved.

Linear Dielectrics1 are materials that obey the equation P=ε0χeE for Es that are not too strong.   χe is called the "electric susceptibility", and it can be thought of as describing how far the charges are free to shift when the electric field pushes on them.  Linear Dielectrics simplify a lot of math and therefore can be quite useful, but that's outside the scope of this brief discussion.  For a more detailed account of dielectrics and polarization, please see The Physics Hypertextbook.

In Linear Dielectrics, the equation we discussed earlier eventually gives us the equation ε=εrε0, where ε describes  an electric field's strength in a given material.  Higher ε means a weaker field, and vice versa.  We can understand this in the context of polarization as ε representing how much the charges in the dielectric shift to counteract the electric field.  We can rearrange the above equation to .

ε0 is the "permittivity of vacuum", and can be thought of as describing the strength of an electric field when there isn't a dielectric around to become polarized and oppose the field.  εr is the ratio between the permittivity of a material and the permittivity of vacuum, so it's a ratio that describes how much weaker an electric field is in a given material relative to vacuum (hence Relative Permittivity).  For example, if εr for a given material is 2, then an electric field in that material will be half as strong as it would be in vacuum.

  1. ^ Griffiths, David J. "Electric Fields in Matter." Introduction to Electrodynamics. 4th ed. N.p.: Prentice Hall, 2013. 185-86. Print.