Radius of Displaced Circle

radius = \sqrt{{(x - h)}^{2} + {(y - k)}^{2}}

$"radius" = sqrt( ( "x" - "h" )^2 + ( "y" - "k" )^2 )$

X-coordinate of the Circle's Center

$"X-coordinate of the Circle's Center"$

Y-coordinate of the Circle's Center

$"Y-coordinate of the Circle's Center"$

X-coordinate of a Point on the Circle

$"X-coordinate of a Point on the Circle"$

Y-coordinate of a Point on the Circle

$"Y-coordinate of a Point on the Circle"$

Tags

This equation computes the radius of a circle given that you know the circle's center and a point anywhere on the circle. The circle's center can be placed anywhere in the X-Y Plane.

Our circle in this equation is centered at the point (h,k) and the point on the circle is (x,y)

Inputs:

h - x-coordinate of the circle's center
k - y-coordinate of the circle's center
x - x-coordinate of a point on the circle
y - y-coordinate of a point on the circle

Note all coordinates ( h, k, x, y ) should be in the same length units.

/attachments/32f2a2d9-e059-11e3-b7aa-bc764e2038f2/RadiusofDisplacedCircle-illustration.png