Discrete Voltage (Analog to Digital)

$V_H = epsilon_V * 2^( n ) + V_L$

$(epsilon_V)"Voltage Resolution"$

$(V_L) "Low Voltage"$

$(n)"Conversion bits"$

Tags

This equation computes the Discrete Voltage acquired from an A/D converter generating N bits.

The choice of highest measurable voltage is made typically to be one voltage resolution less than the nominal high voltage, $V_H$ and this is $V_H$ - $epsilon_V$ .