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CHM1 20 Connection Between Ecell, delta G, and K Collection

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Connection Between Ecell, delta G, and K

From UCDavis Chemwiki

The connection between cell potential, Gibbs free energy and constant equilibrium are directly related in the following multi-part equation:

?Go=?RTlnKeq=?nFEocell

?G: Gibbs Free Energy

?G is the change of Gibbs (free) energy for a system and ?G° is the Gibbs energy change for a system under standard conditions (1 atm, 298K). On an energy diagram, ?G can be represented as:

/attachments/19f93e3f-f145-11e9-8682-bc764e2038f2/delta_g_diagram.png

Where ?G is the difference in the energy between reactants and products. In addition ?G is unaffected by external factors that change the kinetics of the reaction. For example if Ea(activation energy) were to decrease in the presence of a catalyst or the kinetic energy of molecules increases due to a rise in temperature, the ?G value would remain the same.

cell: Standard Cell Potential

cell is the electromotive force (also called cell voltage or cell potential) between two half-cells. The greater the E°cell of a reaction the greater the driving force of electrons through the system, the more likely the reaction will proceed (more spontaneous). E°cell is measured in volts (V). The overall voltage of the cell = the half-cell potential of the reduction reaction + the half-cell potential of the oxidation reaction. To simplify,

Ecell = Ereduction + Eoxidation   or   Ecell = Ecathode + Eanode

The potential of an oxidation reduction (loss of electron) is the negative of the potential for a reduction potential (gain of electron). Most tables only record the standard reduction half-reactions. In other words, most tables only record the standard reduction potential; so in order to find the standard oxidation potential, simply reverse the sing of the standard reduction potential.

*Note: The more positive reduction potential of reduction reactions are more spontaneous. When viewing a cell reduction potential table, the higher the cell is on the table, the higher potential it has as an oxidizing agent. 

Difference between Ecell and Eºcell

Eº cell is the standard state cell potential, which means that the value was determined under standard states. The standard states include a concentration of 1 Molar (mole per liter) and an atmospheric pressure of 1. Similar to the standard state cell potential, Eºcell, the Ecell is the non-standard state cell potential, which means that it is not determined under a concentration of 1 Molar and pressure of 1 atm. The two are closely related in the sense that the standard cell potential is used to calculate for the cell potential in many cases. 

/attachments/19f93e3f-f145-11e9-8682-bc764e2038f2/Ch_21_1.png

Both equations applies when the temperature is 25ºC. Deviations from 25ºC requires the use of the original equation. Essentially, Eº is E at standard conditions

Example 2

What is the value of Ecell for the voltaic cell below:

Pt(s)|Fe2+(0.1M),Fe3+(0.2M)||Ag+(0.1M)|Ag(s) 

Ecell= ?    

SOLUTION

To use the Nersnt equation, we need to establish Eocelland the reaction to which the cell diagram corresponds so that the form of the reaction quotient (Q) can be revealed. Once we have determined the form of the Nernst equation, we can insert the concentration of the species.

Solve:

 Eocell = Eocathode- Eo anode

          = EoAg/Ag  - EoFe3+/Fe2+ 

          = 0.800V-0.771V = 0.029V

Now to determine Ecell for the reaction

Fe2+(0.1M) + Ag+(1.0M)  ? Fe3+(0.20M) + Ag(s)

Use the Nernst equation

Ecell= 0.029V -(0.0592V/1)log [Fe3+]/[Fe2+][Ag]

         =0.029V - 0.0592V*log [0.2]/[0.1]*[1.0]

         =0.011V

K: The Equilibrium Constant

K is the equilibrium constant of a reaction  and is given by the reaction quotient:

/attachments/19f93e3f-f145-11e9-8682-bc764e2038f2/Ch_21_2.png

The Relationship Between The Three

The relationship between ?G, K, and E° cell can be represented by the following diagram.

/attachments/19f93e3f-f145-11e9-8682-bc764e2038f2/triangle_diagram.png

where

  • R = 8.314 J mol C-1
  • T = Temp in K
  • n = moles of e- from balanced redox reaction
  • F = Faraday's constant  = 96,485 C/mol

cell can be calculated using the following formula:

           cell  = E° (cathode) – E° (anode) = E°(Reduction) – E°(Oxidation)

Example 3

Question Find the E° cell for the following coupled half-reactions

SOLUTION

1. Determine the cathode and anode in the reaction

Zn(s) ? Zn2+(aq) + 2e-                  Anode, Oxidation (since Zn(s) increase oxidation state from 0 to +2)

Cu2+(aq) + 2e? Cu(s)                  Cathode, Reduction (since Cu2+(aq) decreases oxidation state from +2 to 0)

2. Determine the E° cell values using the standard reduction potential table

Zn(s) ? Zn2+(aq) + 2e-                  -0.763

Cu2+(aq) + 2e? Cu(s)                  +0.340

3. Use E° cell = E°cathode - E°anode

= 0.340 - (-0.763)

= 1.103 V

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