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CHM1 14Example8 Collection

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Oct 18, 2019, 1:17:50 AM
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Oct 18, 2019, 1:17:50 AM
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19dc9010-f145-11e9-8682-bc764e2038f2

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Example 8

Solution

a) The Lewis diagram

/attachments/19dc9010-f145-11e9-8682-bc764e2038f2/BeCl2.jpg

shows that Be is electron deficient. Therefore BeCl2(g) is a Lewis acid. Because of the lone pairs on the Cl atoms, BeCl2 can also act as a Lewis base, but Cl is rather electronegative and reluctant to donate electrons, so the Lewis base strength of BeCl2 is less than the Lewis acid strength.

/attachments/19dc9010-f145-11e9-8682-bc764e2038f2/BeCL2_lewis_acid.jpg

b) There are lone pairs on O in CH3OH, and so it can serve as a Lewis base.

c) The S atom in SO2 can accept an extra pair of electrons, and so SO2 is a Lewis acid. The O atoms have lone pairs but are only weakly basic for the same reason as the Cl atoms in part (a).

/attachments/19dc9010-f145-11e9-8682-bc764e2038f2/SO2_lewis_acid.jpg

d) Although there are lone pairs on the F atoms, the high electronegativity of F prevents them from being donated to form coordinate covalent bonds. Consequently CF4 has essentially no Lewis-base character. 

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