Solution NaH consists of Na+ and H– ions. Since positive ions repel protons, the H– ion is the only likely base. Again it may be useful to use two hypothetical steps: (l) donation of a proton by an H2O molecule, and (2) acceptance of a proton by the base. As in Example 11.6, we can then sum the steps
`HOH -> cancelH + OH^(-)` step 1
`H^(-) + cancelH^(+) -> H_2` step 2
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`H^(-) + H_2O -> H_2 + OH^(-)` overall
Note that adding a proton to H– balances the excess electron of that ion, producing a neutral H2 molecule. Note also that charges balance in all equations.