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Mass Diffusivity (gas)

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Sep 29, 2022, 12:51:32 AM
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Dec 15, 2014, 1:51:32 AM
`D = (1.858*10^-3 * T^(3/2) * sqrt( (1/M_1) + (1/M_2) )) / (p * (1/2 * (sigma_1 + sigma_2) ) ^2 * Omega )`
` (T)"Temperature"`
`(M_1)"Molar Mass 1" `
`(M_2)"Molar Mass 2" `
` (p)"Pressure"`
`(sigma_1)"Collision Diameter 1" `
`(sigma_2)"Collision Diameter 2" `
` (Omega)"Collision Integral"`
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The Mass Diffusivity of a Gas calculator computes the diffusivity based on two molar masses, an empirical coefficient, the absolute temperature, pressure, average collision diameter and a temperature dependent collision integral.
INSTRUCTIONS: Choose units and enter the following:

  • (T)  Temperature of the gas mixture
  • (p) Pressure of the combined gases
  • (σ1)  Collision diameter of substance 1
  • (σ2)  Collision diameter of substance 2
  • (M1)  Molar mass of substance 1
  • (M2)  Molar mass of substance 2
  • (Ω)  Collision integral for the combining gases

Mass Diffusivity of a Gas(D):  The diffusivity is returned in stokes (cm2/s).

The Math / Science

The Mass Diffusivity of a Gas equation computes the mass diffusivity or diffusion coefficient for a pair of real gases , each with a specified temperature.  The formula used in this mass diffusivity of a gas calculator is:

          ` D = (1.858*10^-3 * T ^(3/2) * sqrt( 1/M_1   + 1/M_2))/(p * (1/2*(sigma_1 + sigma_2))^2 * Omega)`

where:

  • D is the diffusivity of an ideal gas.
  • T - the temperature of the gas mixture
  • p - pressure of the combined gases
  • `sigma_1` - the collision diameter of substance 1
  • `sigma_2` - the collision diameter of substance 2
  • `M_1`  - the molar mass of substance 1
  • `M_2`  - the molar mass of substance 2
  • `Omega` - the collision integral for the combining gases

The diffusivity or diffusion coefficient characterizes the relationship between the molar flux due to molecular diffusion and the gradient force of a c concentration of the material's molecules that drives diffusion.

Diffusivity is specified for one substance relative to another.  In this case there are two substances labeled substance 1 and substance 2.

For a common pair of gases, air and water vapor, we have the gas characteristics:

  • air collision diameter (`sigma_"air"`) - 3.72 Angstroms
  • water collision diameter (`sigma_(H_2O)`) - 2.641 Angstroms
  • air's molar mass (`M_"air"`) - 28.97 g/mol
  • water's molar mass (`M_(H_2O`) - 18.01528 g/mol

This example's environment is characterized by a pressure (p) of 1 atm and a temperature (T) of `25^o C` and the collision integral is 1.005. 

This example will result in a diffusion coefficient (D) for air and water in gaseous combination of 0.282 `cm^2`/s

Diffusivity Equation


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