Circular Shaft and Polar Moment of Inertia

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on

Oct 20, 2021, 2:01:13 PM

Created by

on

Jul 17, 2014, 4:47:31 PM

J = \frac{π \cdot D^{4}}{32}

$J = (pi* D ^4)/32$

(D) Shaft inside Diameter

$(D)"Shaft inside Diameter "$

Polar Moment of Inertia of a circular solid shaft can be expressed as

J = π D⁴ / 32

where

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