Radius of Gyration - Semi Circle

Last modified by

on

Jul 24, 2020, 6:28:07 PM

Created by

on

Jul 31, 2014, 2:58:00 PM

R = \frac{\sqrt{(9 \cdot π^{2} - 64)} \cdot d^{2}}{12 \cdot π}

$R = (sqrt((9*pi^2-64))* d ^2)/(12*pi)$

Diameter of Semi Circle

$"Diameter of Semi Circle"$

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π

$pi$ by MichaelBartmess

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