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Moment of Inertia of a Beam Section

Last modified by
on
Jul 24, 2020, 6:28:07 PM
Created by
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Feb 6, 2017, 3:20:42 AM
Ibeam section=(I¯i+Aidi2)
(w1)Top Flange Width
(w2)Vertical Width
(w3)Bottom Flange Width
(D1)Top Flange Length
(D2)Vertical Length
(D3)Bottom Flange Length

This Moment of Inertia of a Beam Section equation computes the moment of inertia about the x- axis, which is defined at the height of the y-centroid of an I-beam's cross-section. The y-centroid is the center of mass of the beam's cross-sectional sections and we visualize the x-axis passing horizontally through the y-centroid of the cross-section of the beam.  

The centroid is used to compute the moment of inertia of the beam, which represents a body's tendency to resist angular acceleration.  In this case the moment of inertia is about the x-axis through the y-centroid and represents the beams resistance to rotations about the x-axis.

Computing the Centroid of the Beam Section

We split the cross-section into into three segments, each segment having a nice rectangular symmetry. We then calculate the area and y-centroid of each of the three segments and compute the entire centroid as:

y¯=AiyiAi

The three segments are shown in the figure below, where Ai=wiDi:

/attachments/3da0b692-ec1b-11e6-9770-bc764e2038f2/i-beam cross section.png

And the y-centroids of the segments are given as:

  • y1=w3+D2+w12
  • y2=w3+D22
  • y3=w32

Computing the Moment of Inertia

Knowing the y-centroid of the beam's cross section computed above, we then compute the moment of inertia of each of the three segments sing the equation:

I¯i=baseiheighti312

Then we find the distances, d_i, of the segment's centroid from the x-axis (the y-centroid we computed for the beam cross-section earlier).

di=|yi-y¯|

The moment of inertia of the beam in cross-section is then given by:

I(beam section)=(I¯i+Aidi2)

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