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This Moment of Inertia of a Beam Section equation computes the moment of inertia about the x- axis, which is defined at the height of the y-centroid of an I-beam's cross-section. The y-centroid is the center of mass of the beam's cross-sectional sections and we visualize the x-axis passing horizontally through the y-centroid of the cross-section of the beam.
The centroid is used to compute the moment of inertia of the beam, which represents a body's tendency to resist angular acceleration. In this case the moment of inertia is about the x-axis through the y-centroid and represents the beams resistance to rotations about the x-axis.
We split the cross-section into into three segments, each segment having a nice rectangular symmetry. We then calculate the area and y-centroid of each of the three segments and compute the entire centroid as:
The three segments are shown in the figure below, where :
And the y-centroids of the segments are given as:
Knowing the y-centroid of the beam's cross section computed above, we then compute the moment of inertia of each of the three segments sing the equation:
Then we find the distances, d_i, of the segment's centroid from the x-axis (the y-centroid we computed for the beam cross-section earlier).
The moment of inertia of the beam in cross-section is then given by:
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