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Probability of Full House (percentage)

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Jul 24, 2020, 6:28:07 PM
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Apr 5, 2014, 11:55:36 PM
`"Probability"_"Full House" = [((13),(1)) * ((4),(3))* ((12),(1)) * ((4),(2))]" in " ((52),(5))`
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The Probability of a Full House (percentage) constant defines the probability of being dealt a Full House and is represented as a percentage.  The Full House hand is a five card hand having three of five cards being the same value cards and the remaining two card being of the another same value card.  For example:

  • 4 of spades
  • 4 of hearts
  • 4 of diamonds
  • Jack of clubs, and
  • an Jack of spades

would be a Full House.

The number of possibilities of a Full House hands is the number of card values`((13),(1))`; times the number of combinations of three suits chosen from four suits, `((4),(3))`times the times the number of card values different from the card value of the three like cards`((12),(1))`; times the number of combinations of two suits chosen from four suits, `((4),(2))`.  The total number of five card hands possible is computed as `((52),(5))` (see the constant defining number of five card hands), so this constant represent the ratio of number of possible Four of a Kind hands to the number of five card hands possible, `((52),(5))`.

/attachments/c820a258-bd1d-11e3-9cd9-bc764e2038f2/ProbabilityofFullHousepercentage-illustration.png

Additional Resources:

The Poker Calculator provides all the equations, the calculations, to determine the probabilities of success and failure when playing Poker with a standard five card deck.

[Card Games | Poker | Combinatorics | Probability | Chance]


This equation, Probability of Full House (percentage), references 1 page
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