$^{\circ} K$ $""^@"K"$ -to- $^{\circ} F$ $""^@"F"$

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on

Jul 24, 2020, 6:28:07 PM

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on

Jan 16, 2014, 5:40:21 AM

^{\circ} F =^{\circ} K \cdot (\frac{9^{\circ} F}{5^{\circ} K}) - 459.67^{\circ} K

$""^@"F" = ""^@"K" * ((9""^@"F")/(5""^@"K")) - 459.67""^@"K"$

Degrees Kelvin

$"Degrees Kelvin"$

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∘K∘K""^@"K" -to-∘F∘F""^@"F"