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Total Mechanical Energy in a Circular Orbit

Last modified by
on
Jul 24, 2020, 6:28:07 PM
Created by
on
Oct 12, 2016, 3:20:47 AM
Emech=-12G⋅mE⋅mr
(m)Mass
(r)Radius

This equation computes the total mechanical energy, Emech=K+U, where

U=gravitational potential energy=-G⋅mE⋅mr

K=gravitational kinetic energy=12m⋅v2=12m⋅G⋅mEr

So, E=K+U=(12m⋅G⋅mEr)-G⋅mE⋅mr=G⋅mE⋅m2⋅r

Reference

  • Young, Hugh and Freeman, Roger.  University Physics With Modern Physics.  Addison-Wesley, 2008. 12th Edition, (ISBN-13: 978-0321500625 ISBN-10: 0321500628 ) Pg 391, eq 12.9
  • Young, Hugh and Freeman, Roger.  University Physics With Modern Physics.  Addison-Wesley, 2008. 12th Edition, (ISBN-13: 978-0321500625 ISBN-10: 0321500628 ) Pg 394, eq 12.10
  • Young, Hugh and Freeman, Roger.  University Physics With Modern Physics.  Addison-Wesley, 2008. 12th Edition, (ISBN-13: 978-0321500625 ISBN-10: 0321500628 ) Pg 395, eq 12.12
  • Young, Hugh and Freeman, Roger.  University Physics With Modern Physics.  Addison-Wesley, 2008. 12th Edition, (ISBN-13: 978-0321500625 ISBN-10: 0321500628 ) Pg 395, eq 12.13
This equation, Total Mechanical Energy in a Circular Orbit, references 2 pages
This equation, Total Mechanical Energy in a Circular Orbit, is used in 1 page
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