$\int_{a}^{b} (z^{n}) d z$ $int_a^b(z^n)dz$

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MichaelBartmess

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Jul 24, 2020, 6:28:07 PM

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MichaelBartmess

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May 4, 2014, 12:26:41 AM

\int_{a}^{b} (z^{n}) d z = (\frac{b^{n + 1}}{n + 1}) - (\frac{a^{n + 1}}{n + 1}) + C

$int_a^b(z^n)dz = ( "b" ^( "n" +1) / ( "n" +1)) - ( "a" ^( "n" +1) / ( "n" +1)) + "C"$

(a) Lower Limit

$(a)"Lower Limit"$

(b) Upper Limit

$(b)"Upper Limit"$

(n) Exponent

$(n)"Exponent"$

(C) Constant

$(C)"Constant"$

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This is the definite integral of $F (z) = z^{n}$ $F(z) = z^n$ . This is referred to as the "power rule," as it works for all functions of single variable with an exponent.¹

^ Gradshteyn, I.S. and Ryzhik, I.M. Table of Integrals, Series and Products. Seventh Edition. Academic Press - 2007. ISBN-13: 978-0-12-373637-6, ISBN-10: 0-12-373637-4. eq 2.01-1

This equation,

\int_{a}^{b} (z^{n}) d z

$int_a^b(z^n)dz$ , references 0 pages

This equation,

\int_{a}^{b} (z^{n}) d z

$int_a^b(z^n)dz$ , is used in 0 pages

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$\int_{a}^{b} (z^{n}) d z$ $int_a^b(z^n)dz$

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$\int_{a}^{b} (z^{n}) d z$ $int_a^b(z^n)dz$