Polar Moment of Inertia of a circular hollow shaft

Last modified by

on

Jul 24, 2020, 6:28:07 PM

Created by

on

Jul 17, 2014, 5:15:45 PM

J = π \cdot \frac{D^{4} - d^{4}}{32}

$J = pi*( D ^4- d ^4)/32$

shaft outside diameter (mm, in)

$"shaft outside diameter (mm, in)"$

shaft inside diameter (mm, in)

$"shaft inside diameter (mm, in)"$

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π

$pi$ by MichaelBartmess

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