Moment of Inertia - Torus (about axis)

`I = m /4(4* a ^2+3* b ^2)`

Enter a value for all fields

/attachments/04be82fc-4393-11e6-9770-bc764e2038f2/Torus_cycles.png

The Moment of Inertia for a Torus about an axis passing through the center and perpendicular to the diameter is found using the following formula: `I=m/4(4a^2+3b^2)`, where:

`m` = mass
`a` = radius
`b` = cross-sectional radius

References

The formula and equation for Moment of Inertia are from Wikipedia (https://en.wikipedia.org/wiki/List_of_moments_of_inertia).