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Moment of Inertia - Torus (about axis)

Last modified by
on
Jul 24, 2020, 6:28:07 PM
Created by
on
Jul 6, 2016, 4:02:20 PM
`I = m /4(4* a ^2+3* b ^2)`
`(m)"mass"`
`(a)"radius"`
`(b)"cross-sectional radius"`
Tags
Kinematics Moments of Inertia
UUID
04be82fc-4393-11e6-9770-bc764e2038f2

/attachments/04be82fc-4393-11e6-9770-bc764e2038f2/Torus_cycles.png

The Moment of Inertia for a Torus about an axis passing through the center and perpendicular to the diameter is found using the following formula: `I=m/4(4a^2+3b^2)`, where:

  • `m` = mass
  • `a` = radius
  • `b` = cross-sectional radius

References

The formula and equation for Moment of Inertia are from Wikipedia (https://en.wikipedia.org/wiki/List_of_moments_of_inertia).
This equation, Moment of Inertia - Torus (about axis), is used in 1 page
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