Brewster's Angle

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Jul 24, 2020, 6:28:07 PM

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Jun 2, 2016, 1:24:00 AM

θ_{B} = \sin^{- 1} (\sqrt{\frac{1 - β^{2}}{{(\frac{n_{1}}{n_{2}})}^{2} - β^{2}}})

$theta_B = sin^(-1) ( sqrt( (1- beta ^2) / ( ( n_1 / n_2 )^2 - beta ^2) ) )$

β

$beta$

n_{1}

$n_1$

n_{2}

$n_2$

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