THD Triangular Wave

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on

Jul 24, 2020, 6:28:07 PM

Created by

on

Mar 31, 2015, 10:12:34 PM

{THD}_{F} (Triangular Wave) = \sqrt{\frac{π^{4}}{96} - 1}

$"THD"_F("Triangular Wave") = sqrt(pi^4 / 96 -1)$

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The Total Harmonic Distortion (THD) of many standard signals can be computed analytically. 0.12115293 is the THD of a triangular wave.

The formula for the Total Harmonic Distortion of a triangular wave is:

$T H D = \sqrt{\frac{π^{4}}{96} - 1}$ $THD = sqrt( (pi^4)/96 - 1)$

This equation, THD Triangular Wave, references 1 page

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π

$pi$ by MichaelBartmess

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